9. In a 3-digit number, unit's digit, ten's digit and hundred's digit

1.	9. In a 3-digit number, unit's digit, ten's digit and hundred's digit are in the ratio1:2:3. If the difference of original number and the number obtained by rehe digits is 594, find the number
Answer» The number will be 3 digit as its differs 3 digit(594) Let original number be 100x+10y+z Reverted number is 100z+10y+x At the question Original Number=Reverted number+594 which means, original number-reverted number=594 ON PUTTING VALUES 100x+10y+z-(100z+10y+x)=594 100x+10y+z-100z-100y-x=594 99(x-z)=594 Therefore x-z=6 This means ones and hundred digits have difference of 6 Therefore we can substitute any values of x&z to satisfy the condition and y=any value Like if x=9 therefore x=3 903–309=594 {9–3=6} 812–218=594 862–268=594

9. In a 3-digit number, unit's digit, ten's digit and hundred's digit are in the ratio1:2:3. If the difference of original number and the number obtained by rehe digits is 594, find the number

Answer»

The number will be 3 digit as its differs 3 digit(594)

Let original number be 100x+10y+z

Reverted number is 100z+10y+x

At the question

Original Number=Reverted number+594

which means,

original number-reverted number=594

ON PUTTING VALUES

100x+10y+z-(100z+10y+x)=594

100x+10y+z-100z-100y-x=594

99(x-z)=594

Therefore x-z=6

This means ones and hundred digits have difference of 6

Therefore we can substitute any values of x&z to satisfy the condition and y=any value

Like if x=9 therefore x=3

903–309=594 {9–3=6}

812–218=594

862–268=594