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9. In figure 3.89, line 1 touches tecircle with centre O at point P. Qithe mid point of radius OP. RS is a chorthrough Q such that chords RS | lineIfRS 12 find the radius of the circle.

Answer»

OQ is perpendicular to QR .So, OR² = RQ² + OQ²OQ = r/2OR = rRQ = RS/2 = 6 So, r² = 36 + r²/4 which gives r= 4√3



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