9. The length of a line segment AB is of the length of the line segmen

1.	9. The length of a line segment AB is of the length of the line segment CD. The length ofanother line segment EF is of the length of the line segment AB. What fraction of the lengthof CD is equal to the length of EF? If CD = 4 cm then find the length of EF.
Answer» =>AB=2/3CD=>AB=2/3 (4)=8/3cm=> EF=3/8AB=> EF=3/8 (8/3)=1cmso CD=4EF an examination is being held in two parts and three are 572 examinèès in all. 3/11 of the total number of examinees appears in parts onely and 3/13 appears in parts 2 only .the rest appears in both the parts .find the number of candidates appearing in both the parts Length of 1st line segment = AB 2/3 CDLength of 2nd line segment = EF 3/8 ABThe fraction of the CD equal to Length EF Length of CD = 4 cmThe Length of EF =AB = 2/3 of CDAB = 2/3 = 3/8EF = 3/8 of AB EF = 3/8 (8/3) 1cm CD = 4 of EF So, 1 CM = 1/4 CM of EF

9. The length of a line segment AB is of the length of the line segment CD. The length ofanother line segment EF is of the length of the line segment AB. What fraction of the lengthof CD is equal to the length of EF? If CD = 4 cm then find the length of EF.

Answer»

=>AB=2/3CD=>AB=2/3 (4)=8/3cm=> EF=3/8AB=> EF=3/8 (8/3)=1cmso CD=4EF

an examination is being held in two parts and three are 572 examinèès in all. 3/11 of the total number of examinees appears in parts onely and 3/13 appears in parts 2 only .the rest appears in both the parts .find the number of candidates appearing in both the parts

Length of 1st line segment = AB 2/3 CDLength of 2nd line segment = EF 3/8 ABThe fraction of the CD equal to Length EF

Length of CD = 4 cmThe Length of EF =AB = 2/3 of CDAB = 2/3 = 3/8EF = 3/8 of AB EF = 3/8 (8/3) 1cm CD = 4 of EF So, 1 CM = 1/4 CM of EF

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