(9x2 – 12x – 12) ÷ (3x + 2) = …………….. A) 3x + 1 B) 3x

1.	(9x2 – 12x – 12) ÷ (3x + 2) = …………….. A) 3x + 1 B) 3x – 6 C) 6x – 1 D) 6x – 3
Answer» Correct option is B) 3x – 6 Correct option is (B) 3x – 6 \((9x^2–12x–12)\div(3x+2)=\frac{9x^2–12x–12}{3x+2}\) \(=\frac{3(3x^2-4x-4)}{3x+2}\) \(=\frac{3(3x^2-6x+2x-4)}{3x+2}\) \(=\frac{3(3x(x-2)+2(x-2))}{3x+2}\) \(=\frac{3(3x+2)(x-2)}{3x+2}\) = 3 (x - 2) = 3x – 6

(9x2 – 12x – 12) ÷ (3x + 2) = …………….. A) 3x + 1 B) 3x – 6 C) 6x – 1 D) 6x – 3

Answer»

Correct option is B) 3x – 6

Correct option is (B) 3x – 6

\((9x^2–12x–12)\div(3x+2)=\frac{9x^2–12x–12}{3x+2}\)

\(=\frac{3(3x^2-4x-4)}{3x+2}\)

\(=\frac{3(3x^2-6x+2x-4)}{3x+2}\)

\(=\frac{3(3x(x-2)+2(x-2))}{3x+2}\)

\(=\frac{3(3x+2)(x-2)}{3x+2}\)

= 3 (x - 2)

= 3x – 6