1.

A 0.02 kg weight produces an extension of 0.02 m in a vertical spring. A mass of 0.1kg is suspended at its bottam and is left after putting down. What is the period of oscillation ?

Answer»


SOLUTION :`K = MGL =0.02 xx10//0.02=10Nm^(-1),T=2pisqrt(m//k)= 2pisqrt(0.1//10)=0.63` SECOND


Discussion

No Comment Found