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A 0.1 kg body moves at a constant speed of 10 m/s. It is pushed by applying a constant force for 2 s. Due to this force, it starts moving exactly in the opposite direction with a speed of `4 m//s`. ThenA. the deceleration of the body is `7 m//s^(2)`B. the magnitude of change in momentum is 1.4 kg-m/sC. impulse of the force is 1.4 N-sD. All of the above |
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Answer» Correct Answer - D `a=(v-u)/(t)=(-4-10)/(2)=-7m//s^(2)` The magnitude of change in momentum `=|m(v-u)|=14kg-m//s`=Impulse Now, F = ma = 0.7 N |
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