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A `0.1` molal solution of `NaCI` found to be isotomic with `1%` urea solution , calculate `alpha` and `i` for `NaCI`A. `i = 1.66 alpha= 0.66`B. `i = 2.66 alpha= 0.66`C. `i = 1.66 alpha= 2.66`D. `i = 3.66 alpha= 2.66` |
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Answer» Correct Answer - a `i_(1)(CM)_(1) = i_(2) (CM)_(2)` `i_(1) (0.1) + (((W)/(V))% xx 10)/(M W) rArr i_(1) = (1 xx 10)/(60 xx 0.1)` `rArr i = (10)/(6) = 1.66 alpha = (i - 1)/(n - 1)` `alpha = (1.66 - 1)/(2-1)` |
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