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A 0.10 M solution of a mono protic acid (`d=1.01g//cm^(3)`) is 5% dissociated what is the freezing point of the solution the molar mass of the acid is 300 and `K_(f)(H_(2)O)=1.86C//m`A. `-0.189^(@)C`B. `-0.194^(@)C`C. `-0.199^(@)C`D. none |
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Answer» Correct Answer - C Mass of 1 litre of solution =1010 gram mass of solvent =1010 `-300xx0.1=980` gram `m=(0.1)/(0.98)=0.102` `DeltaT_(f)=iK_(f)m=(1+alpha)K_(f)m` `impliesDeltaT_(f)=0.199^(@)C` `impliesT_(f)=0-0.199^(@)C=-0.199^(@)C` |
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