A 0.2 kg object at rest is subjected to a force (0.3hati – 0.4hatj)N. What is its velocity vector after 6 sec

A 0.2 kg object at rest is subjected to a force (0.3hati – 0.4hatj)N

1.	A 0.2 kg object at rest is subjected to a force (0.3hati – 0.4hatj)N. What is its velocity vector after 6 sec
Answer» `(9hati-12hatj)` `(8hati-16hatj)` `(12hati-9hatj)` `(16hati-8hatj)` SOLUTION :`VECA=(VECF)/(m), vecv=vecu+vecat`