

InterviewSolution
Saved Bookmarks
1. |
A `0.2075 g` sample of an oxide of cobalt on analysis was found to contain `0.1475 g` cobalt. Calculate the empirical formula of the oxide. `(Co = 59 "amu")` |
Answer» Weight of `O = 0.2075 - 0.1475 = 0.06 g` Mol of `Co = (0.1475)/(59) = 0.0025` Mol of `O = (0.06)/(16) = 0.003` Simplest ratio of `Co = (0.0025)/(0.0025) = 1.0` Simplest ratio of `O = (0.003)/(0.0025) = 1.5` Ratio of `Co : O = 1 : 1.5 = 2 : 3` Formula `= Co_(2) O_(3)` |
|