(A) 0.7 Mif 100 ml of 1M H2SO4 solution is mixed with 100 ml of 9.8%(w

1.	(A) 0.7 Mif 100 ml of 1M H2SO4 solution is mixed with 100 ml of 9.8%(w/w) H2so, solution (d-1 gi I), then(A) concentration of solution r(C) mass of H,SO, in the solution is 98 g (D) mass of H2SO, in the solution is 19.6 gemains sarme(B) volume of splution become 200 ml00 ml fn3nf 0 3 d CaGl, solution +400 ml of 0.1 M HCl solution, correct datas islarentiotion f catin(st n 7 w
Answer» calculate the molarity of 100 ml 9.8% ( w/w) H2SO4 total mass of solution is = 1001 = 100gm and 9.8% of 100gm = 9.8g is the mass of H2SO4 so, moles of H2SO4 = 9.8/98 = 0.1 => M = 0.1/100ml = 0.1/0.1L = 1M now adding it with 100ml , of 1M H2SO4 total volume = 200ml and total mol = 0.2 so, molarity = 0.2/0.2 = 1M , total mass of H2SO4 = 0.298 = 19.6g so, option A ✓ option B ✓ option D ✓ A solution of sodium carbonate contains 53.0g of solute in 215ml of solution what is it's molarity

(A) 0.7 Mif 100 ml of 1M H2SO4 solution is mixed with 100 ml of 9.8%(w/w) H2so, solution (d-1 gi I), then(A) concentration of solution r(C) mass of H,SO, in the solution is 98 g (D) mass of H2SO, in the solution is 19.6 gemains sarme(B) volume of splution become 200 ml00 ml fn3nf 0 3 d CaGl, solution +400 ml of 0.1 M HCl solution, correct datas islarentiotion f catin(st n 7 w

Answer»

calculate the molarity of 100 ml 9.8% ( w/w) H2SO4

total mass of solution is = 100*1 = 100gm and 9.8% of 100gm = 9.8g is the mass of H2SO4

so, moles of H2SO4 = 9.8/98 = 0.1 => M = 0.1/100ml = 0.1/0.1L = 1M

now adding it with 100ml , of 1M H2SO4

total volume = 200ml and total mol = 0.2

so, molarity = 0.2/0.2 = 1M , total mass of H2SO4 = 0.2*98 = 19.6g

so, option A ✓ option B ✓ option D ✓

A solution of sodium carbonate contains 53.0g of solute in 215ml of solution what is it's molarity