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A 1 L flask cantaing vapours of methyl alcohol (molar mass 32) at a pressure was `10^(-3)` mm. How many molecules of mehtyl alcohol are left in the flask ? |
Answer» `P_(1)=10^(-3)mm` `V_(1)=1000cm^(3)` `T_(1)=298K` For converting this volume to the volume at STP, apply `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))` i.e., `(10^(-3)xx1000)/(298)=(760xxV_(2))/(273)` or `V_(2)=1.205xx10^(-3)cm^(3)` Now `22400cm^(3)` at STP `=6.02xx10^(23)` molecule `therefore1.205xx10^(-3)cm^(3)` at STP `=(6.02xx10^(23))/(22400)xx1.205xx10^(-3)` molecules `=3.24xx10^(16)` molecules |
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