A 10.0 cm column of air is trapped by a column of 4 cm long Hg in a capillary tube of uniform bore when the tube is held horizontally at 1 atm. The length of the air column when the tube is held vertically with the open end up is:Given: Patm=76 cm of Hg

A 10.0 cm column of air is trapped by a column of 4 cm long Hg in a ca

1.	A 10.0 cm column of air is trapped by a column of 4 cm long Hg in a capillary tube of uniform bore when the tube is held horizontally at 1 atm. The length of the air column when the tube is held vertically with the open end up is:Given: Patm=76 cm of Hg
Answer» A $10.0 cm$ column of air is trapped by a column of 4 cm long $H g$ in a capillary tube of uniform bore when the tube is held horizontally at $1 atm$ . The length of the air column when the tube is held vertically with the open end up is: Given: $P_{a t m} = 76$ cm of Hg