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A 10 g sample of KCIO2, gave on completedecomposition , 2.24 L of oxygen at STP. What isthe percentage purity of the sample of potassiumchlorate? |
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Answer» 2KClO3 ---> 2KCl + 3O2Therefore, 2 mol of KClO3 gives 3 mol of O2122.5 g of KClO3 gives 22.4X 3 L of O210 g of KClO3 = 0.081 mol (approx.)2.24 L of O2 = 0.1 molif 3 mol of O2 is obtained from 2 mol of KClO30.1 mol of O2 is obtained from 2/3 X 0.1 = 0.06 mol of KClO3Therefore, amount of pure potassium chlorate in sample = 0.06 mol% age purity = 0.06 / 0.081 X 100 = 74.07% |
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