1.

A 10 kg mass moves x-axis. Its acceleration as function of its position is shown in the figure. What is the total work done on the mass by the force as the mass moves from x = 0 to x = 8 cm ? A. 8 JB. `10^(-2) J`C. `8 xx 10^(-2) J`D. `4 xx 10^(-2) J`

Answer» Correct Answer - C
Work done = m `xx` (area under the graph)
`=10xx(1)/(2)xx20xx8xx10_(-4)J=8xx10_(-2)J`


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