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A `100 mL` of tap water was titrated with `M//50 HCl` with methyle orange as indicator. If `30 mL of HCl` were required. Calculate the hardness of `CaCO_(3)` per `10^(3)` parts of water. The hardness is temporary.A. `150 "ppm"`B. `600 "ppm"`C. `275 "ppm"`D. `300 "ppm"` |
Answer» Correct Answer - D Meq. of `CaCO_(3)`= Meq. of `Ca(HCO_(3))_(2)` = Meq. of HCl `(W)/(100//2)xx 1000= (1)/(50) xx 30` `W_(CaCO_(3))= (3 xx 100 )/(5 xx 2000) = 0.03 g` `therefore 100 mL " of "H_(2)O " contins " Ca^(2+)= (0.03 xx 10^(6))/(100)= 300 "ppm"` |
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