1.

A 100 mL sample of water was treated to convert any iron present to Fe^(2+). Addition of 25 mL of 0.002 M K_(2)Cr_(2)O_(7) resulted in thereaction : 6Fe^(2+)+Cr_(2)O_(7)^(2-)+14H^(+)rarr6Fe^(3+)+2Cr^(3+) + 7H_(2)O The excess K_(2)Cr_(2)O_(7) was back-titrated with 7.5 mL of 0.01 M Fe^(2+) solution. Calcution the parts per million (ppm) of iron in the water sample.

Answer»


ANSWER :126 PPM


Discussion

No Comment Found