A `100 mu F` capacitor in series with a `40 Omega` resistance is connected to a `100 V_(1) 60 Hz` supply. Calculate (i) the reactance (ii) the impedance and (iii) maximum current in the circuit.

A `100 mu F` capacitor in series with a `40 Omega` resistance is conne

1.	A `100 mu F` capacitor in series with a `40 Omega` resistance is connected to a `100 V_(1) 60 Hz` supply. Calculate (i) the reactance (ii) the impedance and (iii) maximum current in the circuit.
Answer» (i) Reactance, `X_(C)=(1)/(2pi f c)` `=(1)/(2xx3.142xx60xx100xx10^(-6))=(10^(6))/(1.2xx10^(4)xx3.142)=(10)/(0.12xx3.142)` `=(10)/(0.37704)=26.5 Omega`. (ii) Impedance, A= `sqrt(R^(2)+X_(C)^(2))` `=sqrt((40)^(2)+(26.5)^(2))=sqrt(1600+702.25)=sqrt(2302.25)=47.98 = 48 Omega`. (iii) `V_(eff)=100V` `I_(0)=(V_(0))/(Z)=(sqrt(2V_(eff)))/(Z)=(1.414xx100)/(48)=2.95A`.

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A `100 mu F` capacitor in series with a `40 Omega` resistance is connected to a `100 V_(1) 60 Hz` supply. Calculate (i) the reactance (ii) the impedance and (iii) maximum current in the circuit.

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