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A `100 Omega` resistance and a capacitor of `100 Omega` reactance are connected in series across a `220` V source. When the capacitor is `50%` charged, the peak value of the displacement current isA. `4.4 A`B. `11sqrt(2) A`C. `2.2 A`D. `11 A` |
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Answer» Correct Answer - d `(i_(d))_(max)=(i_(c))_(max)=i_(0)(epsilon_(0))/(Z)=(200sqrt(2))/(sqrt(100^(2)+100^(2)))` `implies (i_(d))_(max)=(200sqrt(2))/(100sqrt(2))=2.24` As we are asked amplitude of displacement current. So, need not worry about charge on capacitor. |
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