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A 100 pF capacitor is connected to a 230 V. 50Hz AC source. The rms value of conduction current will be |
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Answer» RMS value of conduction current, \(I=\frac{V}{X_C}\) \(I=V\omega C=230V\times300rad/s\times10^{-10}F\\I=6.9\times10^{-6}A\) |
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