Saved Bookmarks
| 1. |
A 100 watt buble emits monochromatic light of wavelength 400 nm. Then the number of photons emitted per seccond by the buble is nearly -A. `2xx10^(20)`B. `2xx10^(18)`C. `2xx10^(16)`D. `2xx10^(22)` |
|
Answer» Correct Answer - A A 100 watt buib emits …….. Power of the bulb = 100 watt `100 Js^(-1)` Energy of one photon `E = hv = hc//lambda` `= 6.62xx10^(-34)Jsxx3xx10^(8)ms^(-1)//400xx10^(-8)m` `= 4.96xx10^(-19)J` Number of photons emitted `= 100 Js^(-1)//4.96xx10^(-19)J` `= 2.01xx10^(20)s^(-1)` |
|