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A 1000 kg engine pulls a train of 4 wagons each of 2500 kg along a horizontal railway track. If the engine exerts a force of 50000 N on wagons and track offers force of friction 10000 N, then calculate (i) The net accelerating force (ii) The acceleration of the train (iii) The force of wagon-1 on wagon-2 |
Answer» Solution : FORCE EXERTED by the engine is `F_(1)=50,000 N ` Frictional force exerted by the track, `F_(2)= -10000 N` Negative sign shows that frictionis opposite to the directionof motion. (i) Therefore, net accelerating force `(VECF)=vecF_(1)+vecF_(2)` `=50,000 +(-10,000)` `=40,000 N` (ii) Mass of each wagon of the train = 2500 kg Number of wagons of the train = 4 `therefore underset("(without engine)") ("Mass of the train(m)")=2500 xx 4=10,000 kg` Net accelerating force acting on the train is F = 40,000 N From, F = ma `a=(F)/(m)=(40,000)/(10,000)=4m//s^(2)` (iii) Mass of ONE wagon `(m_(1))=2500 kg` Acceleration of the train `a=4m//s^(2)` Force exerted by wagon-1 on wagon-2 is the accelerating force for the three rear wagons.  `therefore F'=3xx2500 xx 4m//s^(2)` `=30,000N` |
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