1.

A wire is bent to form a semicircle of the radius a. The wire rotates about its one end with angular velocity omega . Axis of rotation is perpendicular to the plane of the semicircle . In the space , a uniform magnetic field of induction B exists along the aixs of rotation as shown in the figure . Then -

Answer»

<P>potential DIFFERENCE between p and Q is equal to` 2 B omega a^2`
potential difference betweenp andQ is equal to`2 pi ^2B omega a^2`
p is at HIGHER potential than Q
potential difference betweenP and Q iszero.

Solution :`E=1/2 Bl^2 omega =1/2B(2A)^2 omega =2 B omega a^2`


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