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A 100wartbulbemitsmonochromaticlight ofwavelength 400 bn, Calculatethe numberofphotonsemittedper secondby the bulb. |
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Answer» SOLUTION :Powerof the bulb - 100 walt= 10 `js^(-1)` Energyof one photonE `hv = (hc )/(lambda)= (6.626xx 10^(34) Js xx3.0xx 10^(8) MS^(-1))/( 400 xx 10^(9) m)` Noof photon4.9695 `xx 10^(19)` energyfrom 1photon 100J senergyfromhowmanyphoton Numberof photonsemited `=(1xx 100 Js^(-1))/(4.9695 xx 10^(19) J)= 2.0123 xx 10^(20) s^(-1)` |
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