InterviewSolution
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InterviewSolution
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A `10g` bullet is short from a `5kg` gun with a velocity of `400m//s`. What is the speed of recoil of the gun? |
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Answer» Here, mass of bullet, `m_(1)= 10g= 10xx10^(-3)kg= 10^(2)kg`, mass of gun, `m_(2)= 5kg` velocity of bullet, `v_(1) = 400m//s`, speed of recoil of gun `v_(2) = ?` As total momentum of bullet and gun after firing = total momentum before firing, `m_(1)v_(1)+m_(2)v_(2)=0` or `v_(2) = -(m_(1)v_(1))/m_(2)= -(10^(-2)xx400)/5` or `v_(2)= -0.8m//s` Negative sign shows that the gun moves in a direction opposite to that of the bullet. |
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