1.

A 10gmixture of Cu_(2)S and CuS was treated with 200 mL of 075M MnO_(4)^(-)in acid solution producing SO_(2), CU^(2+) and Mn^(2+). The SO_(2) was boiled off and the excess of MnO_(4)^(-). The SO_(2) was boiled off and the excess of MnO_(4)^(-) was titrated with 175 mL of 1M Fe^(2+) solution. Caculaate % fo CuSin original mixture.

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ANSWER :`57.94%`


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