A 10kg mass is resting on a horizontal surface and horizontal force of 80N is applied. If mu = 0.2, the ratio of acceleration without and with friction is (g = 10ms^(-2)).

A 10kg mass is resting on a horizontal surface and horizontal force of

1.	A 10kg mass is resting on a horizontal surface and horizontal force of 80N is applied. If mu = 0.2, the ratio of acceleration without and with friction is (g = 10ms^(-2)).
Answer» `(3)/(4)` `(4)/(3)` `(1)/(2)` `(4)/(2)` Solution :`F_("net")=ma, a_(1)=(F)/(m), a_(2)=(F-mu_(K)MG)/(m)`