1.

a={1,2,3,4,5}, Relation R on A is defined by R={(x,y)//x lt y" and "|x^(2)-y^(2)|lt 9} then R =

Answer»

`{(1,1),(2,2),(3,3),(4,4),(5,5)}`
`{(2,1),(3,2),(3,2),(4,3),(5,4)}`
`{(1,2),(1,3),(2,3),(3,4),(4,5)}`
`{(1,2),(1,3),(2,3),(3,4)}`

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