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A 140g ball, in horizontal flight with a speed `v_(1)` of 39.0 m/s. is sturck by a bat. After leaving the bat, the ball travel in the opposite direction with speed `v_(2)=39.0 m//s`. If the impact time `Deltat` for the ball-bat collision is 1.20ms, what average net force acts on the ballA. 1308NB. 1090NC. 9100ND. 980N |
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Answer» Correct Answer - C Here mass of ball, m=140g=0.14kg initial velocity `v_(1)=39m//s`, final velocity `v_(2)=-39m//s`, impact time `Deltat=1.20ms` impulse, I=change in momentum. `Deltap=mv_(2)-mv_(1)=m(v_(2)-v_(1))` `=0.14(-39-39)` `=-10.92 kg m//s` `therefore F_("mv")=(I)/(Deltat)=(10.92kg m//s)/(1.20xx10^(-3)s)=91xx10^(2)N` |
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