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A 15 gm ball is shot from a spring gun whose spring has a force constat 600N/m. The spring is compressed by 5 cm. The greatest possible horizontal range of the ball for this compression is (g=10m//sec^(2)) |
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Answer» Solution :`R_("MAX")=(U^(2))/g` But K.E ACQUIRED by ball =P.E of spring gun `implies1/2 m u^(2)=1/2kx^(2)impliesu^(2)=(kx^(2))/m`……….2 From EQUATIONS 1 and 2 `R_("max")=(kx^(2))/(mg)=(600xx(5xx10^(-2))^(2))/(15xx10^(-3)xx10)=10m` |
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