A 1m long wire having tension of 100 N and of linear mass density 0.01 kg/m is fixed and A and free at end B. the point C which is 20cm from end B is constrained to be stationary. To create resonance in the wire, the minimum frequency of the tuning fork will be :

A 1m long wire having tension of 100 N and of linear mass density 0.01

1.	A 1m long wire having tension of 100 N and of linear mass density 0.01 kg/m is fixed and A and free at end B. the point C which is 20cm from end B is constrained to be stationary. To create resonance in the wire, the minimum frequency of the tuning fork will be :
Answer» <html><body><p>125 Hz<br/>150 Hz<br/>300 Hz<br/>275 Hz</p>Solution :Length of <a href="https://interviewquestions.tuteehub.com/tag/bc-389540" style="font-weight:bold;" target="_blank" title="Click to know more about BC">BC</a> to AC is `(20)/(<a href="https://interviewquestions.tuteehub.com/tag/80-337972" style="font-weight:bold;" target="_blank" title="Click to know more about 80">80</a>)=(1)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)` <br/> So, value of loops in BC to AC will also be `1 : 4` <br/> `f_(1)=(1)/(4(0.2))sqrt((T)/(mu))=125 Hz` <br/> `f_(2) = (3)/(4(0.2))sqrt((T)/(mu))=275 Hz`.</body></html>

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A 1m long wire having tension of 100 N and of linear mass density 0.01 kg/m is fixed and A and free at end B. the point C which is 20cm from end B is constrained to be stationary. To create resonance in the wire, the minimum frequency of the tuning fork will be :

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