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A 2.05MB 0.50MC 1.78MD 1.02M |
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Answer» As We know that Density of solution = Mass of solution / Volume of solution therefore , volume of solution = Mass / density = 120+1000 g/ 1.15 g ml-1 = 1120 *100 / 115 = 973.91 ml = 974 * 10 -3 litres Now , n (no. of moles of solute) = 120 g / 60.05 g = 2 mol [since, molecular mass of urea is 60.05 g] Now ,M(Molarity) = n (no. of moles of solute)/ Volume of solution in litres Molarity = 2 / 974 * 10-3 Molarity = 2000/974 = 2.05 M |
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