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A 2.5 m long straight wire having mass of 500 g is suspended in mid air by a uniform horizontal magnetic field B. If a current of 4 A is passing through the wire then the magnitude of the field is `("Take g "10 m s^(-2))`A. 0.5TB. 0.6TC. 0.25TD. 0.8T |
Answer» Correct Answer - A Here, `m=500g = 0.5kg, I=4A, l=2.5m` As `F=Il B sin 90^(@)," "(because theta=90^(@) and F=mg)` `therefore" "B=(mg)/(Il)=(0.5xx10)/(4xx2.5)=0.5T` |
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