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a) \( 2 \cos ^{2} \theta-1 \)b) 1-2 \( \sin ^{2} \theta \)c) \( \cos ^{2} \theta-\sin ^{2} \theta \)d) \( \cos ^{2} \theta+\sin ^{2} \theta \)6. \( \cos ^{2} \theta= \)a) \( \frac{1+\cos 2 \theta}{2} \)b) \( \frac{1-\cos 2 \theta}{2} \)c) \( 1-\sin ^{2} \theta \)d) \( \cos (2 \theta) \) |
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Answer» sin2x= 2sinx . cosx |
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