InterviewSolution
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InterviewSolution
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A 2 kg stone at the end of a string 1 m long is whirled in a vertical circle at a constant speed of 4 m/s. The tension in the string will be 52 N when the stone is (Take g = 10 m/s2) (A) at the top of the circle (B) at the bottom of the circle (C) halfway down (D) at any position other than that in (A), (B) and (C) |
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Answer» Answer is (B) at the bottom of the circle Using, \(\frac{mv^2}{r}\) = \(\frac{2\times(4)^2}{1}\) = 32N It is clear that tension will be 52 N at the bottom of the circle because we know that, TBottom = mg + \(\frac{mv^2}{r}\) |
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