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A 200 turn closely wound circular coil of radius 15 cm carries a current of 4 A. The magnetic moment of this coil isA. `36.5A m^(2)`B. `56.5A m^(2)`C. `66.5A m^(2)`D. `108A m^(2)` |
Answer» Correct Answer - B The magnetic moment is given by `|vecm|=NIA=NI pi r^(2)=200xx4xx3.14xx(15xx10^(-2))^(2)` `=200xx4xx3.14xx15xx15xx10^(-4)="56.5 A m"^(2)` |
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