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A 200V, 10 hp, 4 poles, 60 Hz, Y-connected induction motor had full load slip of 5%. Then the rotor speed of the motor with respect to stator is?(a) 1710 rpm(b) 1800 rpm(c) 90 rpm(d) 3510 rpmI have been asked this question by my school principal while I was bunking the class.The origin of the question is Machine Ratings topic in section Rating and Loss Dissipation of Electrical Machines

Answer»

The correct answer is (a) 1710 RPM

For explanation: Synchronous SPEED, Ns = 120*f/P = 120*60/4 = 1800 rpm

Rotor speed = (1-slip)*Ns = 0.95*1800 = 1710 rpm.



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