1.

A 25watt bulbemitsmonochromaticyellowlightofwavelengthof 0.57 mu m.Calculate therate ofemissionof quanta per second.

Answer»

SOLUTION :ENERGYOF bulb=25watt=25 `js^(-1)` energy(E )
E = HV= `(HC)/(LAMBDA)`
`=(6.626 xx 3.0)/( 0.57)xx 10^(20)J` perphoton
Quantum velocity`=("Emitenergybulb")/( "Emitenergyof photon")`
`=(25 js^(-1)xx 0.57)/(6.626 xx 3.0 xx 10^(20)J)`
`7.169 xx 10^(19)s^(-1)`
`=7.17 xx 10^(19) s^(-1)`


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