(a-2b-3c)2expand

1.	(a-2b-3c)2expand
Answer» (a−2b−3c)2According to the equation ,(a+b+c)2\xa0= a2\xa0+ b2\xa0+ c2\xa0+ 2ab + 2bc + 2caSo we get,Using the formula we can it write it as(a−2b−3c)2\xa0= a2+(−2b)2+(−3c)2+2a(−2b)+(2(−2b)(−3c)+2(−3c)aOn further calculation we get,(a−2b−3c)2\xa0= a2\xa0+ 4b2\xa0+ 9c2\xa0− 4ab + 12bc − 6ac

Discussion