1.

A+2B→c+D. If dA/dt=5×10-4 mol l-1 sec -1 then -dB/dt is 

Answer» The rate of disappearance of each reactant and rate of appearance of each product in the given reaction is related in the following way

-dA/dt =1/2(-dB/dt)=dC/dt=dD/dt

So dB/dt = 2(dA/dt)

Hence the answer is 10^-3mol l^-1 sec^-1


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