A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid p

1.	A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?
Answer» Length of the wire, l = 3 cm = 0.03 m Current flowing in the wire, I = 10 A Magnetic field, B = 0.27 T Angle between the current and magnetic field, θ = 90° Magnetic force exerted on the wire is given as: F=BIlsinθ = 0.27 × 10 × 0.03 sin90° = 8.1 × 10^–2N Hence, the magnetic force on the wire is 8.1 × 10^–2 N. The direction of the force can be obtained from Fleming’s left hand rule.

A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

Answer»

Length of the wire, l = 3 cm = 0.03 m
Current flowing in the wire, I = 10 A
Magnetic field, B = 0.27 T
Angle between the current and magnetic field, θ = 90°
Magnetic force exerted on the wire is given as:

F=BIlsinθ
= 0.27 × 10 × 0.03 sin90°
= 8.1 × 10^–2N
Hence, the magnetic force on the wire is 8.1 × 10^–2 N. The direction of the force can be obtained from Fleming’s left hand rule.

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A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

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