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A `3*0cm` wire carrying a current of `10A` is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be `0*27T`. What is the magnetic force on the wire? |
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Answer» Here, `l=3*0cm=3xx10^-2m`, `I=10A`, `B=0*27T`, `theta=90^@`, `F=?` `F=Bil sin theta=0*27xx10xx(3xx10^-2)xxsin90^@=0*27xx10xx3xx10^-2xx1=8*1xx10^-2N` The direction of force is perpendicular to the direction of current as well as of magnetic field. |
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