1.

A `3:2` molar mixture of `N_(2)` and `CO` is present in a vessel at `500 "bar"` pressure. Due to hole in the vessel, the gas mixture leaks out. The composition of mixture effusing out initially isA. `n_(N_(2)):n_(CO): : 1:2`B. `n_(N_(2)):n_(CO): : 6:1`C. `n_(CO):n_(N_(2)): : 1:2`D. `n_(CO):n_(N_(2)): : 2:3`

Answer» Molar ratio of `N_(2)` and `CO` is `3:2`, i.e., `300 bar` and `200 bar`, respectively.
`(n_(N_(2)))/(n_(CO))=sqrt((m_(CO))/(mN_(2)))xx(P_(N_(2)))/(P_(CO))=(300)/(200)=(3)/(2)`


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