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A 3-phase, 50 Hz, 6-pole induction motor has a shaft output of 10kW at 930 rpm. Friction and windage losses is 1% of the output. Total stator losses is 600W. What is the stator input?(a) 10860 W(b) 10100 W(c) 11460 W(d) 11000 WI had been asked this question in an interview.Origin of the question is Operating (or Performance) Characteristics of Induction Motors topic in chapter Induction Machines of Electrical Machines

Answer»

The CORRECT OPTION is (c) 11460 W

Explanation: Full load slip = 1000-930/1000 = 0.07.

Friction losses = 0.01*10000 = 100 W

Pm = 10000+100 = 10100 W

Rotor input = 10100/0.93 = 108060 W

Stator input = Pg+600 = 11460 W.



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