1.

A 30 kg box has to move up an inclined plane of slope 30^(@) to the horizontal with a uniform velocity of 5 ms^(-1).If the frictional force retarding the motion is 15ON, the horizontal force required to move the box up is(g=10ms^(-2))

Answer»

`300xx(2)/(sqrt3)N`
`300xx(sqrt3)/(2)N`
`300N`
`150N`

Solution :`F cos theta=mg sin theta +f, f=mu_(s)N`


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