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A 300 M Long Train Crosses A Platform In 39 Sec While It Crosses A Signal Pole In 18 Sec. What Is The Length Of The Platform? |
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Answer» Speed = 300/18 = 50/3 m/sec. Let the length of the platform be x METERS. Then, (x + 300)/39 = 50/3 Speed = 300/18 = 50/3 m/sec. Let the length of the platform be x meters. Then, (x + 300)/39 = 50/3 3x + 900 = 1950 => x = 350 m. |
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