A 300 Meter Long Train Crosses A Platform In 39 Seconds While It Cros

1.	A 300 Meter Long Train Crosses A Platform In 39 Seconds While It Crosses A Signal Pole In 18 Seconds. What Is The Length Of The Platform?
Answer» SPEED = [300 / 18] m/sec = 50/3 m/sec. LET the length of the platform be X meters. Then, x + 300 / 39 = 50/3 3(x + 300) = 1950 è x = 350M. Speed = [300 / 18] m/sec = 50/3 m/sec. Let the length of the platform be x meters. Then, x + 300 / 39 = 50/3 3(x + 300) = 1950 è x = 350m.

A 300 Meter Long Train Crosses A Platform In 39 Seconds While It Crosses A Signal Pole In 18 Seconds. What Is The Length Of The Platform?

Answer»

SPEED = [300 / 18] m/sec = 50/3 m/sec.

LET the length of the platform be X meters.

Then, x + 300 / 39 = 50/3

3(x + 300) = 1950 è x = 350M.

Speed = [300 / 18] m/sec = 50/3 m/sec.

Let the length of the platform be x meters.

Then, x + 300 / 39 = 50/3

3(x + 300) = 1950 è x = 350m.