1.

A `3000 cm^(3)` tank contains oxygen at `20^(@)C` and the gauge pressure is `2.5 xx 10^(6) Pa`. Find the mass of the oxygen in the tank. Take 1 atm `= 10^(5) Pa`.

Answer» Correct Answer - `103.8 gram`
Pressure of oxygen gas,
`P_(1) = 2.5xx10^(6) Pa + 1 atm`
`=25 xx 10^(5) +10^(5) = 26 xx 10^(5) Pa`
`V_(1) = 3000 c.c., T_(1) = 20 + 273 = 293 K`,
`P=10^(5)Pa, V =? T=273 K`.
`V = (P_(1)V_(1)T)/(T_(1)P) = ((26 xx 10^(5))xx(3000)xx 273)/(293 xx 10^(5)) c.c.`
Mass of this volume of oxygen = `(32 V)/(22400)`
`=(32 xx 26 xx 3000 xx 273)/(22400 xx 293) = 103.8 gram`


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