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A `30kg` box has to move up an inclined plane of slope `30^(@)` the horizontal with a unform velocity of `5 ms^(-1)`. If the frictional force retarding the motion is `150N`, the horizontal force required to move the box up is `(g =ms^(-2))` .A. `300xx(2)/sqrt3N`B. `300xx(sqrt3)/(2)N`C. `300N`D. `150N` |
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Answer» Correct Answer - A `F cos theta = mg sin theta + f, f = mu_(s) N` |
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