1.

A 35.3 g of element M is reacted with nitrogen to produce 43.5 g of compound M3N2. What is (i) the molar mass of the element and (ii) name of the element?

Answer»

A 35.3 g of element M is reacted with nitrogen to produce 43.5 g of compound M3N2.

Generally, the equation for the Chemical Reaction  is mathematically given as

3M+N2=M3N2

Therefore

moles of N2 is given as

m= mass of N2/molar mass

Where

mass of N2=43.5-35.3

mass of N2=8.2

Therefore

m =8.2/32

m=0.25625mole

Since 2 moles of N2 reacts with 3mols of M

Hence, 0.25625 mole of N2 reacts with 3mole of M

x=3/2*0.256

x=0.384mol

In conclusion, the molar mass of M

M = mass of x/mole of x

M = 35.3/0.384

M=91.927g/mol



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